Mar 21, 2023 · The code in the question is pseudo-code; there, := represents assignment. For future visitors, though, the following might be more relevant: the next version of Python (3.8) …

Since Python 3.8, code can use the so-called "walrus" operator (:=), documented in PEP 572, for assignment expressions. This seems like a really substantial new feature, since it allows this …

Jan 20, 2014 · There is a code and in class' method there is a line: object.attribute |= variable I can't understand what it means. I didn't find (|=) in the list of basic Python operators.

Aug 23, 2014 · I think this would violate Python's object model or variable/naming scheme. A name does not represent one object only, but just points to an object under the hood. Using …

Jun 14, 2012 · The way you describe it is absolutely not possible. Assignment to a name is a fundamental feature of Python and no hooks have been provided to change its behavior. …

C and many other languages have a conditional (AKA ternary) operator. This allows you to make very terse choices between two values based on the truth of a condition, which makes …

Jan 6, 2012 · I also feel a bit unconfortable using that kind of expressions. In Learning Python 4ed it is called a "somewhat unusual behavior". Later Mark Lutz says:...it turns out to be a fairly …

Apr 24, 2012 · This new operator is also known as the walrus operator. It will introduce a lot of potential savings w.r.t. computation/memory, as can be seen from the following snippet of the …

Assignment (sub-)expressions (x := y) are supported since Python 3.8 (released Oct. 2019), so you can indeed now rewrite your example as lst.append(x := X()). The proposal, PEP 572, was …

Oct 24, 2011 · For the future time traveler from Google, here is a new way (available from Python 3.8 onward): b = 1 if a := b: # this section is only reached if b is not 0 or false. # Also, a is set …