Feb 22, 2025 · calendar module in Python provides the calendar.isleap (y) function which checks if a given year is a leap year. This built-in function simplifies leap year validation with a single call returning True or False. Program uses calendar.isleap (y) to check if year is a leap year simplifying logic.

Jul 24, 2012 · By definition, a leap year is divisible by four, but not by one hundred, unless it is divisible by four hundred. Here is my code: def leapyr(n): if n%4==0 and n%100!=0: if n%400==0: print(n, "is a leap year.") elif n%4!=0: print(n, "is not a leap year.") print(leapyr(1900))

Write a Python Program to Check Leap Year or Not by using the If Statement, Nested If Statement, and Elif Statement with an example. Before we get into the leap year program, let us check the logic and see the definition behind this.

# Python program to check if year is a leap year or not year = 2000 # To get year (integer input) from the user # year = int(input("Enter a year: ")) # divided by 100 means century year (ending with 00) # century year divided by 400 is leap year if (year % 400 == 0) and (year % 100 == 0): print("{0} is a leap year".format(year)) # not divided ...

Sep 6, 2023 · For identifying leap years in Python, the Modulo operator “ % ” is considered the most efficient and straightforward approach. In this approach, we will check if a year is evenly divisible by 4 and not divisible by 100 (except when divisible by 400), you can accurately determine the leap years.

May 9, 2023 · In this example, we are using the isleap() function of the calendar module to check if a number passes to it as a leap year or not. If the isleap() functions returns the True value, it means the number is a leap year.

Jan 31, 2024 · To list leap years in a specified period, use calendar.isleap() as a condition in list comprehension. Note that in range(start, end), end is not included. Python's standard library includes the datetime module for handling dates and times. The datetime module provides datetime.datetime for both date and time, and datetime.date for dates only.

Yes, you can use this Python program for leap year for any year. Simply pass the desired year as an argument to the is_leap_year() function, and it will return True if it is a leap year and False if it is not.

Feb 13, 2024 · In this guide, we will explore several ways to determine if a given year is a leap year, including the use of conditional statements, functions, and library supports. Understanding these methods can enhance your coding skills and broaden your problem-solving strategies in …

Aug 10, 2016 · leap_years = filter(calendar.isleap, range(2016, 2036)) The former should be preferred unless you have good reason to use filter (hint: you probably don't) N.B. that this gives you which years are leap years (if any), rather than a boolean "There are leap years" or "There aren't leap years."