[Update: for Python3 (the currently maintained versions of Python) the range() function always returns the dynamic, "lazy evaluation" iterator; the older versions of Python (2.x) which returned a statically allocated list of integers are now officially obsolete (after years of …

Aug 27, 2012 · python 2.7. Is it possible to do this: print "Enter a number between 1 and 10:" number = raw_input("> ") if number in range(1, 5): print "You entered a number in the range of 1 to 5" elif number in range(6, 10): print "You entered a number in the range of 6 to 10" else: print "Your number wasn't in the correct range"

Mar 28, 2012 · For your case using range(10,-10,-1) will be helpful. The first argument refers to the first step, the second one refers to the last step, and the third argument refers to the size of that step. When your range is ascending, you do not need to specify the steps if you need all numbers between, range(-10,10) or range(-10,-5).

Aug 16, 2013 · simple_range = [ x*0.1 for x in range(-100, 100) ] By changing the range count to 100 I now get my range of -10 through 10 by using the standard range function. So if you need it by 0.2 then just do range(-200, 200) and so on etc

One thing you can do is to set your axis range by yourself by using matplotlib.pyplot.axis. matplotlib.pyplot.axis. from matplotlib import pyplot as plt plt.axis([0, 10, 0, 20]) 0,10 is for x axis range. 0,20 is for y axis range. or you can also use matplotlib.pyplot.xlim or matplotlib.pyplot.ylim. matplotlib.pyplot.ylim. plt.ylim(-2, 2) plt ...

I would like to select a range for a certain column, let's say column two. I would like to select all values between -0.5 and +0.5. How does one do this? I expected to use -0.5 < df["two"] < 0.5 But this (naturally) gives a ValueError: ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). I tried

Sep 2, 2011 · $ python -m timeit "[9-i for i in range(10)]" 1000000 loops, best of 3: 1.54 usec per loop martineau's answer (readable if you are familiar with the extended slices syntax): $ python -m timeit "range(10)[::-1]" 1000000 loops, best of 3: 0.743 usec per loop Michał Šrajer's answer (the accepted one, very readable):

Here, range(1, len(xs)+1); If you expect the output to start from 1 instead of 0, you need to start the range from 1 and add 1 to the total length estimated since python starts indexing the number from 0 by default.

Mar 8, 2023 · Below are few possible ways, ordered from best to worse performance (i.e first one will perform best) # Old school check if 10000 <= b and b <=30000: print ("you have to pay 5% taxes") # Python range check if 10000 <= number <= 30000: print ("you have to pay 5% taxes") # As suggested by others but only works for integers and is slow if number in …

Python does not dynamically increase the size of an array when you assign to an element. You have to use a.append(element) to add an element onto the end, or a.insert(i, element) to insert the element at the position before i.