Jan 30, 2023 · In early versions of Python, the sort function implemented a modified version of quicksort. However, in 2.3 this was replaced with an adaptive mergesort algorithm, in order to provide a stable sort by default.

The function you pass in to key is given each of the items that are being sorted, and returns a "key" that Python can sort by. So, if you want to sort a list of strings by the reverse of the string, you could do this: list_of_strings.sort(key=lambda s: s[::-1]) This lets you specify the value each item is sorted by, without having to change the ...

For anyone who is new to python or coming from a c++ background. we want to replicate to use of the call-back function here like c++. I tried this with the sorted() function. For example: if we wanted to sort this list according to marks (ascending order) and if marks are equal then name (ascending order)

Jun 8, 2012 · Timsort is a hybrid sorting algorithm, derived from merge sort and insertion sort, designed to perform well on many kinds of real-world data. It was invented by Tim Peters in 2002 for use in the Python programming language. The algorithm finds subsets of the data that are already ordered, and uses the subsets to sort the data more efficiently.

Feb 18, 2021 · Any comparison-based sort must take at least O(n log n). Without knowledge of the data and a specialized sort to take advantage of that (e.g. radix sort), this is the bound. It's not much of a stretch to say that a general (comparison-based) sort in a standard library will have this complexity bound. –

Apr 16, 2017 · I have a list a = ['L', 'N', 'D']. I want to reverse the order of elements in a and get b = ['D', 'N', 'L']. I tried this: a = ['L', 'N', 'D'] b = sorted(a, reverse ...

Jul 3, 2013 · You probably don't really want to sort those elements as strings, but as numbers (so 4.918560000 will come before 10.277200999 rather than after). The best solution is most likely to store the numbers as numbers rather than strings in …

Use list.sort() when you want to mutate the list, sorted() when you want a new sorted object back. Use sorted() when you want to sort something that is an iterable, not a list yet. For lists, list.sort() is faster than sorted() because it doesn't have to create a …

Oct 27, 2012 · This is not based on efficiency, and has to be done with only a very very basic knowledge of python (Strings, Tuples, Lists basics) so no importing functions or using sort/sorted. (This is using Python 2.7.3).

Aug 21, 2011 · I have a function that takes an object as an argument and gives me a number. I wish to use this number as the key to sort my list. If I were to iterate over the list I would do something like: sorted_list = [] for object in my_list_of_objects: i = my_number_giving_function(object) sorted_list.insert(i, object)