Feb 19, 2019 · Well you can simply use Math.pow(a,b) as you have used earlier and just convert its value by using (int) before it. Below could be used as an example to it. int x = (int) …

Nov 17, 2013 · A solution I made that may help you understand a few things more clearly. // Make it ready for the loop, no point calling Math.pow() every loop - expensive import static …

Dec 19, 2012 · 2) And instead of ^, you can change that calculation as below using Math.pow() bmi = (weight/(Math.pow(height/100, 2))); 3) Math.pow() method has below definition. …

I got as far as calculating the user's monthly interest rate based on their input, and also began translating my professor's formula into Java's language. However, I can't figure out how to use …

May 2, 2015 · Option 2: without using Math.pow public class PowerCalculator{ /** * Calculate the non-negative power of an integer number. If a negative power is input, the method returns 1.

Sep 26, 2012 · I am having problems converting this formula V = 4/3 π r^3. I used Math.PI and Math.pow, but I get this error: ';' expected Also, the diameter variable doesn't work.

Feb 13, 2014 · EDIT: If it is required to have a method that returns a float you can still use the Math.pow and then include your conversion back from double to float and include your own …

Jul 7, 2016 · But if I simply use Math.pow(number,1.0/3.0) it works for much bigger numbers and computes it in no time. So, what is the algorithm that Math.pow() uses that gives an instant …

Sep 30, 2014 · The formula for the volume of a sphere is V = 4/3 * PI * radius^3 Convert the formula to Java and add a line which calculates and stores the value of volume in an …

Mar 25, 2016 · Math.pow uses doubles as it produces both large and tiny numbers depending on the inputs. e.g. even 4^20 will not fit in an int. If you want to round the result to a long you can …