May 11, 2010 · For example, double value is 3.72 and if I use format() function, new double value changes 3,72 and If I wanna set this new value to double property, it will be throwed exception of NumberFormatException: For input string: "3,72". But you got this logical operation, not function.

// assuming you want to round to Infinity. double tip = (long) (amount * percent + 0.5) / 100.0; This result is not precise but Double.toString(double) will correct for this and print one to two decimal places. However as soon as you perform another calculation, you can get a result which will not be implicitly rounded.

Sep 30, 2008 · What I would like is a method to convert a double to a string which rounds using the half-up method - i.e. if the decimal to be rounded is 5, it always rounds up to the next number. This is the sta...

Jul 16, 2014 · BigDecimal.valueOf(double val) - Translates a double into a BigDecimal, using the double's canonical string representation provided by the Double.toString(double) method. new BigDecimal(double val) - Translates a double into a BigDecimal which is the exact decimal representation of the double's binary floating-point value.

I have a double value = 1.068879335 i want to round it up with only two decimal values like 1.07. I tried like this DecimalFormat df=new DecimalFormat("0.00"); String formate = df.format(value); ...

Oct 27, 2013 · Math.ceil will always round UP or as said above, in excess. Math.round will round up or down depending on the decimals. If the decimal is equal or higher than 5, then it's rounded up. decimal => 5. (1,5 = 2) If the decimal is less than 5, then it's rounded down. decimal < 5. (1,45 = 1) Examples of Math.ceil and Math.round: The code Below would ...

Mar 5, 2014 · I have these two variables double num = 540.512 double sum = 1978.8 Then I did this expression double total = Math.round((num/ sum * 100) * 10) / 10; but I end up with 27.0.

The Math.round function is overloaded When it receives a float value, it will give you an int. For example this would work. int a=Math.round(1.7f); When it receives a double value, it will give you a long, therefore you have to typecast it to int. int a=(int)Math.round(1.7); This is done to prevent loss of precision.

Jun 13, 2016 · As a previous poster suggested, When you are doing numeric calculations, use java.math.BigDecimal. However, there is a gotcha to using BigDecimal. When you are converting from the double value to a BigDecimal, you have a choice of using a new BigDecimal(double) constructor or the BigDecimal.valueOf(double) static factory method. Use the static ...

There's no difference in internal representation between 2 and 2.00. You can use Math.round to round a value to the nearest integer - to make that round to 2 decimal places you could multiply by 100, round, and then divide by 100, but you shouldn't expect the result to be exactly 2dps, due to the nature of binary floating point arithmetic.