In the left case, Min and Max of data turned out to be the same, thus the vertical line has no height. For the second case, Mathematica fails to draw the line due to automatically selected PlotRange (selecting PlotRange -> All helps). Furthermore, if the plot is part of a dynamical setup, and the vertical plot range is manipulated, the line ...

May 24, 2010 · So for a vertical line at located at x=2*pi, we can do something like this: Plot[{Sin[x], 10^10 (x - 2 \[Pi])}, {x, 0, 10}, PlotRange -> {-1, 1}] click to see the image. Note that the term 10^10 mimics an infinite slope. If you do not use the option PlotRange -> {-1, 1}, the "dominant" function is the straight line so the Sin[x] function do ...

Mar 30, 2020 · The Plot will give your horizontal line. If you don't give that a PlotRange then it will only show the diagram from x=-3 to x=5 and you want to have that plot large enough so that it will include your vertical line when x=10. Then the Graphics will give your vertical line. And the Show will combine both those.

Apr 10, 2018 · Please help. Trying to find area between three curves, e^-x, x = 2, y = 1. Can't find out how to plot x = 2. Don't want to use Epilogue unless it can shade the area enclosed by the three curves.

I want to plot a vertical line on a graph. The plot range on the graph ranges from 0 - 12. I want the vertical line at x-axis = 0.8, but the vertical height going from 0 to 7 only. I am not sure how to do this. I tried with gridlines but there seems no easy way around that.

Now I plot it: Plot[f[x],{x,120,150}] If I want to highlight a specfic point: x1 = {{130,f[130]}} I would like to have a vertical line going from the x-Axis to that point and ending at that point (like: Filling -> Bottom) and a horizontal line going from the y-Axis and ending at that point. How can I do it ?

Dec 15, 2011 · First, consider Plot[] which "generates a plot of f as a function of x from xmin to xmax" (I'm quoting the Mathematica documentation). You can't use it to plot a vertical line satisfying the equation x = x0, because the latter is not a function of x: instead of being single-valued, it has infinitely many values at x0.

Jul 17, 2020 · plt1=Plot[Sin[x],{x,0,2π}] I now want to add two vertical lines, one at x=3π/4 abd on at x=5π/4. In addition, I want to shade the region between those two lines. My initial idea was to use ParametricPlot to draw the line, and I hoped it would have a Fillingoption similar to that of Plot, but it does not. The next idea was to use

Jun 15, 2016 · There is a good demonstration of how ExclusionsStyle works here.Check Plot[Floor[x], {x, 0, 5}, ExclusionsStyle -> {Red, Blue}]

Mar 24, 2021 · I would like to represent i) the K^s value as a vertical line in the right diagram and ii) identify the intersection of the vertical line with the downward-sloping curve with "E" (as well as vertical and horizontal values) as in the left diagram.