Sep 16, 2016 · Use a while loop instead, if( guess.equals(secret) ) { System.out.println( "enter" ); } else { System.out.println( "try again" ); { System.out.println("Secret word") guess = input.next(); Apart from this, the for loop have the following syntax, This …

Oct 10, 2013 · There are two possible scenarios: Number One is to use arrays where each items is held as a string and you loop 20 times. Number Two is to use an ARRAY LIST where each list item holds the name of each kitten whilst you loop 20 times. Use for loop and array that'll contain the data: inputs[i] = scanner.nextLine();

Nov 5, 2018 · Use a while loop above input line as: while(true) And, use if condition to break. break; Also, condition for leap year is wrong in your code. It should be: //its a leap year. //its not. PS: As in comments, I'll give a complete code: System.out.println("Enter a year to check if it is a leap year"); while(true){

Mar 11, 2025 · In this tutorial, we’ve explored how to implement a while loop in Java that continuously requests user input. We covered basic input handling, input validation, and even created a simple menu-driven program.

Jan 8, 2024 · In this article, we’ve explored how to write a Java method to read user input until a condition is met. The two key techniques are: Using the Scanner class from the standard Java API to read user input; Checking each input line in an infinite loop; if …

Feb 2, 2024 · In this article, we’ll discuss using the do while loop in Java. The do-while loop is similar to other loops like for and while loops in java. It is also used to iterate over and over, depending on a specific condition.

In Java, a while loop is used to execute statement(s) until a condition is true. In this tutorial, we learn to use it with examples. First of all, let's discuss its syntax: while (condition(s)) {// Body of loop} 1. If the condition(s) holds, then the body of the loop is executed after the execution of the loop body condition is tested again.

Apr 25, 2021 · How can I loop this bit-of code so that it repeats until user gives the correct Input ? The correct input is number (Integer). I have tried using boolean and While loop, but I have created only an infinite loop. try { System.out.println("Enter age : "); newPerson.setAge(userInput.nextInt()); userInput.nextLine();

Oct 15, 2014 · Don't compare strings with ==. Instead do if (playAgain.equals ("Y")). When the user enters "Y", you need to start the loop all over again. Exactly what @Arvy said. Also, Random.nextInt(10) gives you a value between 0 - 9 so you should either say Random.nextInt(11) OR change your first if statement to if(guess < 0 || guess > 9)

To optimize user input loops, consider the following: – Validate user input within the loop to ensure it meets the required criteria. – Use flags or specific conditions to break out of the loop. – Avoid complex conditions in the loop header for readability.