The general contract of Comparable.compareTo(o) is to return. a positive integer if this is greater than the other object. a negative integer if this is lower than the other object. 0 if this is equals to the other object. In your example "ab2".compareTo("ac3") == -1 and "ab2".compareTo("ab3") == -1 only means that "ab2" is lower than both "ac3 ...

Sep 12, 2012 · I know that compare and compareTo returns an int value. For example: Returns 0 if a equal b -1 if a < b +1 if a > b sort method makes a call to either compareTo or compare() methods. But how does sort method arranges the list when compare or …

Sep 22, 2010 · this.compareTo(that) returns . a negative int if this < that; 0 if this == that; a positive int if this > that; where the implementation of this method determines the actual semantics of < > and == (I don't mean == in the sense of java's object identity operator) Examples "abc".compareTo("def") will yield something smaller than 0 as abc is ...

Jan 7, 2009 · comes from the java.util.Comparator interface, implemented in a separate class that compares another class's objects to give a negative int value for the first object being less than, 0 for equals, or positive value for greater than the second object. It is needed when you cannot make a class implement compareTo() because it is not modifiable.

Nov 21, 2017 · Java provides two interfaces to sort objects using data members of the class: Comparable and Comparator interfaces. Java Comparable interface. Java Comparable interface is used to order the objects of user-defined class. This interface is found in java.lang package and contains only one method named compareTo(Object).

Jul 3, 2014 · Basically after the change, your compareTo does not check for "is smaller" any more but checks for "is bigger". So even though System.out.println(e[1].compareTo(e[0])); returns 1 in both cases, in the first case it tells you "e[1] is bigger than e[0]" and in the second case it tells you "e[1] is smaller than e[0]". It's kind of tricky, think ...

Apr 10, 2015 · A primitive type is not a Java Object and so the method compareTo does not exist. Use the Java Object Double and not the primitive type: Double sides1 = Double.valueOf(1.0); Double sides2 = Double.valueOf(1.3); int compared = sides1.compareTo(sides2); Edit - do not take from that that all Java Objects have the compareTo(..) method.

Feb 5, 2012 · int cmp = Integer.compare(a, b); // in Java 7 int cmp = Double.compare(a, b); // before Java 7 It's best not to create an object if you don't need to. Performance wise, the first is best. If you know for sure that you won't get an overflow you can use. int cmp = a - b; // if you know there wont be an overflow. you won't get faster than this.

Jul 22, 2009 · compareTo() is the standard way to represent a default total ordering on non-primitive types in Java. The advantage of returning an integer is that it only needs to be called once to distinguish the three cases <, == and >. (The alternative approach of for example using methods equals() and greaterThan() would need two calls.)

Sep 11, 2019 · int comparison = stringListIterator.next().compareTo(newCity); Part of your confusion is because this line of code does too many things. To understand what it is doing, split it into two lines: String city = stringListIterator.next(); int comparison = city.compareTo(newCity); Now you can also add output to see what is happening: