I want to create a string using an integer appended to it, in a for loop. Like this: for i in range(1, 11): string = "string" + i But it returns an error: TypeError: unsupported oper...

Aug 8, 2011 · Since Python is a strongly typed language, concatenating a string and an integer, as you may do in Perl, makes no sense, because there's no defined way to "add" strings and …

Oct 11, 2012 · This is not the problem requested. for example, it would not work if you try to concatenate 10 and 200, it would result in 1200 instead of 10200. you could use def f(x, y): …

As a rule, Python doesn't implicitly convert objects from one type to another 1 in order to make operations "make sense", because that would be confusing: for instance, you might think that …

Aug 18, 2012 · To print strings and numbers in Python, is there any other way than doing something like: first = 10 second = 20 print "First number is %(first)d and second number is …

message is now an int type, so for char in message: causes TypeError: 'int' object is not iterable. message is converted to int to make sure the input is an int. Set the type with str() Only …

Python is an interesting language in that while there is usually one (or two) "obvious" ways to accomplish any given task, flexibility still exists. s = "string" i = 0 print (s + repr(i)) The above …

Yeah, there are some differences between Python 2 and 3, which is the reason that Python 2 is still used today. The Python wiki has a page on the subject. For learning purposes, it doesn't …

Nov 23, 2011 · I need to "concatenate to a string in a for loop". To explain, I have this list: list = ['first', 'second', 'other'] And inside a for loop I need to end with this: endstring = …

Jun 23, 2021 · Python: concatenate string and int in a loop. 0. How to concatenate integers variables as a string? 0. Q ...