Mar 18, 2012 · If you want to remove multiple object from a list. There are various ways to delete an object from a list. Try this code. a is list with all object, b is list object you want to remove. example : a = [1,2,3,4,5,6] b = [2,3] for i in b: if i in a: a.remove(i) print(a) the output is [1,4,5,6] I hope, it will work for you

Feb 2, 2014 · [[item for item in seq if some_condition] for seq in my_list] Note that if you want to remove just one item then list.remove, list.pop and del are definitely going to be very fast, but using these methods while iterating over the the list can result in unexpected output. Related: Loop “Forgets” to Remove Some Items

Jul 12, 2012 · node_list.remove(removed) ValueError: list.remove(x): x not in list but the list just contains addresses that act like pointers right? it should match up the same addresses. i printed out the address of removed and the whole node_list (only 10 items for now don't fear) print out: (the last item in node_list matches the address of removed:

Sep 29, 2018 · But maybe an example that tackles the exact case the OP described would be desirable (that is: remove object with name "item2"). – Floella Commented Aug 3, 2022 at 23:44

Mar 9, 2009 · The old list object is hence dereferenced and hence garbage collected (provided the original list object is not referenced by any variable other than a). This makes this method very inefficient and it can also produce undesirable side effects (especially when other variables point to the original list object which remains un-modified).

IIUC, you know how to remove the item from the list but are concerned about destroying it. Every value in Python is an object, and every item in a list is a reference to a value. Think about it as pointers. When you remove an object from the array and there is no variable, array or object property referencing it, the object will be wiped from ...

May 8, 2010 · arr = [1, 1, 3, 4, 5, 2, 4, 3] # to remove first occurence of that element, suppose 3 in this example arr.remove(3) # to remove all occurences of that element, again suppose 3 # use something called list comprehension new_arr = [element for element in arr if element!=3] # if you want to delete a position use "pop" function, suppose # position 4 # the pop function also returns a value removed ...

while thing in some_list: some_list.remove(thing) Simple enough, probably my choice.for small lists (can't resist one-liners) 2) Duck-typed, EAFP style: This shoot-first-ask-questions-last attitude is common in Python. Instead of testing in advance if the object is suitable, just carry out the operation and catch relevant Exceptions:

When you call list.remove, the function searches for the item in the list, and deletes it if found. When searching, it needs to perform a comparison, comparing the search item to every other list item. You're passing an object to remove. A user defined object. They do not behave the same way as, say, integers would, when performing comparisons.

Feb 4, 2012 · Iterate through the list, find the object and its position, then delete it: for i, o in enumerate(obj_list): if o.attr == known_value: del obj_list[i] break Share