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answered Feb 9, 2018 at 9:09
It's because the scan.nextDouble() method does not consume the last newline character of your input, and thus that newline is consumed in the next call to scan.nextLine().
For this a blank scan.nextLine() call after scan.nextDouble() to consume rest o...
public class newLineIssue {public static void main(String args[]) throws InterruptedException {Scanner scan = new Scanner(System.in);int i = scan.nextInt();double d = scan.nextDouble();scan.nextLine();String s = scan.nextLine();System.out.println("String: " + s);Content Under CC-BY-SA license Print entire line string with Java Scanner - Stack Overflow
Feb 9, 2018 · use System.out.print () instead of System.out.println () which breaks the line. Put a scan.nextLine() after the scan.nextInt() and scan.nextDouble() to read the rest of the lines and …
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Java User Input (Scanner class) - W3Schools
To use the Scanner class, create an object of the class and use any of the available methods found in the Scanner class documentation. In our example, we will use the nextLine() method, …
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Java Scanner String input example - TheServerSide
Jul 23, 2022 · To take String input from the user with Java’s Scanner class, just follow these steps. Import java.util.*; to make Java’s Scanner class available; Use the new keyword to …
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Jan 5, 2024 · In this quick tutorial, we’ll illustrate how to use the Java Scanner class – to read input and find and skip patterns with different delimiters. 2. Scan a File. First – let’s see how to …
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How do I ensure print output is shown before scanning user ... - Reddit
Apr 18, 2022 · System.out.print("> "); String input= scanner.nextLine(); System.out.println("Some message"); What ends up happening is that the user is asked for input before the prompt, then …
Java Scanner (With Examples) - Programiz
The Scanner class of the java.util package is used to read input data from different sources like input streams, users, files, etc. In this tutorial, we will learn about the Java Scanner and its …
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