Feb 20, 2015 · I was wondering if we can make an array with a size specified by the user. Ex: int a; cout<<"Enter desired size of the array"; cin>>a; int array[a]; The above program won't work …

Although, depending on what you need, maybe you can just let it grow naturally by using push_back. A lower-level alternative is to use dynamically allocated arrays: int userSize; cin …

Dec 12, 2016 · My array size is a constant set at 50. I want the user to be able to enter no more than 50 numbers but have the option to enter less. My idea would be to to enter 'q' to quit to …

Mar 6, 2024 · In this article, we will learn how to dynamically resize an array in C++. Example: In C++, the size of an array is static, but we can also create a dynamic array in C++ using the …

Jan 7, 2013 · So I want to create an array size depending on what the user specifys. I have tried this in visual studio 2010 and it tells me it has to be a constant value. How do I let a user input …

This tutorial focuses on the method to dynamically allocate memory and change array size according to the user input. This is a very useful method used in programming as it ensures …

Jul 12, 2021 · You can always use a dynamic array int size; std::cin >> size; int* arr = new int[size]; Though its highly discouraged. std::vector is the go to option for dynamic arrays

Feb 2, 2024 · The userInput is a function defined to get user input for the array size and elements. It declares an integer variable size to store the size of the array and then prompts the user to …

Nov 10, 2015 · I'm trying to write a program that will have a user input size for an array, and then take values into that array. I initially tried int sz = 51; double Arr[sz];

Jun 27, 2015 · I want to declare a char array with not initial size. Later I will prompt the user to enter in a sentence. This input will be stored in the char array using getline. But how do I make …