Mar 10, 2021 · I'm trying to show some tickets on the screen from an APi. I did the petition with a fetch and the console is showing me an array with the data that I want to be shown on screen. Everything seems to be okay but the tickets ain't in the screen.

Apr 6, 2022 · It returns a object with data that has an array. Im not sure if im saying it correctly, but when it displays in the console it says object when I click the object drop down it shows data with an array of information. The only missing part is how you loop over your data and add items to your list, so here's a quick example. cities: [

Apr 21, 2021 · Overall you code looks fine, but I find Array.map() useful in this case. And then combine it with Array.join() for tuning it into a string.

Jul 25, 2024 · In this tutorial you’ll learn how to fetch data from a remote API and output that data into a HTML page. Learning to work with API data is a crucial skill to learn as a web developer. Many websites and applications rely on internal or external APIs to …

Feb 26, 2022 · As a short term fix, you can use a CORS proxy, like: https://cors-anywhere.herokuapp.com/. There is a working pen here. It works as a short term solution but not for production. I’d recommend learning more about CORS and finding a more kosher solution. The API also has to serve over https if your page is served over https.

Sep 3, 2020 · appendChild expects Node: https://developer.mozilla.org/en-US/docs/Web/API/Node/appendChild not an array. Also your array has syntactic errors (at …

You actually trying to destructure title and description from an array (data.articles). This cannot be done. You should iterate through the array and then append the text nodes. Change your code to this

JavaScript does not support associative arrays. You should use objects when you want the element names to be strings (text). You should use arrays when you want the element names to be numbers.

Dec 29, 2009 · The best you can do is to always explicitly set the array's name when you create it: var z = []; z.name = 'z'; You could do this by having a function makeArray that sets the name passed as an argument: function makeArray(name) { var arr = []; arr.name = name; return arr; }

Aug 28, 2017 · \$\begingroup\$ @Iwrestledabearonce using let in global scope is not pointless. Unlike the respective var declaration, the variable name is not accessible on the window object. So given a top-level let foo = 'bar';, window.foo does not exist. \$\endgroup\$ –