Now we need to find the strings that contain at least 5 consecutive letters sorted alphabetically, or in other words ... HAVING MIN(lvl) > 0 ) SQL needs to use nested subqueries and CONNECT BY to ...

and I'm afraid we don't have any newer analysis of this sort." The list may be 20 years old, but I'm going with it. The alphabet isn't like ice cream flavors or musical acts -- no new, trendy ...

This project is based on the DataCamp course Data Manipulation in SQL and expands it with structured, business-oriented documentation and reproducible examples. It showcases advanced data analysis ...