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Let, initial1st_no=0, 2nd_no=1 [first & second number are always constant] Fibonacci Value (2) = 1st_no + 2nd_no = 0+1 = 1 (3rd_no) Fibonacci Value (3) = 2nd_no + 3rd ...

multiplication of size 2 by 2. And on the other hand complexity of bruteforce solution is O(n).

Lois Borny works on the product review section of The Independent, IndyBest, where she helps readers to save money and shop savvy, scouting out the very best deals and sharing her tried and tested ...