From the graph, we can also see that the y-intercept is 6, therefore we can say that the equation of the straight line is \(y = mx + 6\). Now we need to find the gradient.

All quadratic functions have the same ... of the points where the graph crosses the x-axis. Draw the graph of \(y = x^2 -x – 4 \) and use it to find the roots of the equation to 1 decimal ...