A recurring decimal exists when decimal ... 20 divided by 6 is 3 remainder 2. Convert \(0. \dot{1}\) to a fraction. Firstly, write out \(0. \dot{1}\) as a number, using a few iterations (repeats ...

In this case, the recurring numbers are the 5 and the 7, so the answer is \(0. \dot{5} \dot{7}\). Convert \(\frac{5}{6}\) to a recurring decimal. Divide 5 by 6. 5 divided by 6 is 0, remainder 5 ...