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Each octal digit (0-7) is mapped to a 3-bit binary number. The logical expression for the encoder can be represented using a truth table, with each octal digit as one input and the corresponding 3-bit ...
Boolean expression for this gate is. Y = (A ⊕ B) Output (A ⊕ B) = A.B + A.B. The truth table above shows clearly demonstrates that the output of an Exclusive-OR gate will only goes “HIGH” when both of ...
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